If 900j/g of heat is exchanged
WebIf 900J/g of heat is exchanged at boiling point of water then what is increase in entropy? Please scroll down to see the correct answer and solution guide. Right Answer is: … Web12 feb. 2024 · The specific heat of aluminum is 900 J/ (kg·K) and that of water is 4190 J/ (kg·K). What is the final temperature of the system, assuming no heat is exchanged with the surroundings? Advertisement asuwafoh Answer: 61.4 °C Explanation: Heat lost by the water = heat gained by the aluminum container. cm (t₁-t₃) = c'm' (t₃-t₂)..........................
If 900j/g of heat is exchanged
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WebIf 900 J/g of heat is exchanged at the boiling point of water, then what is an increase in entropy? A 43.4 J/mole B 87.2 J/mole C 900 J/mole D 86.8 J/mole Hard Solution Verified by Toppr Correct option is A) Solve any question of Chemical Thermodynamics with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions WebThe specific heat of aluminum is 900J/ (kg·K). How much heat flows from the water to the aluminum, assuming no heat is exchanged with the surroundings? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer
WebThe specific heat of aluminum is 900 J/(kg·K) and that of water is 4190 J/(kg·K). What is the final temperature of the system, assuming no heat is exchanged with the surroundings? … Web6 jun. 2024 · we know, H = mcT where, H = Heat content of the body m = Mass, c = Specific heat T = Change in temperature According to to the Principle of Calorimetry The net heat remains constant i.e. ⇒ the heat given by water = heat accepted by the aluminum container. ⇒ 330 x 1 x (45 - T) = 855 x x (T - 10) ⇒ 14,850 - 330T = 183.21T - 1832
WebWhat is the specific heat of the metal, assuming no heat is exchanged with the surroundings? The specific heat of aluminum is 900J/ (kg*K). A 425-g piece of metal at 100°C is dropped into a 100-g aluminum cup containing 500 g of water at 15C. The final temperature of the system is 40°C. WebObject 1 has three times the specific heat capacity and four times the mass of Object 2. The two objects are heated from the same initial temperature, T0, to the same final temperature Tf. During this process, if Object 1 absorbs heat Q, the amount of heat absorbed by Object 2 will be 1/12 Q. 4/3 Q. 6Q. 12Q. 3/4 Q. 1/12 Q
WebEm The enthalpy of vaporisation of per mole of ethanol (b.p. = 79.5°C and AS = 109.8 JK- mof) is :- (1) 27.35 KJ/mol (2) 32.19 KJ/mol (3) 38.70 KJ/mol (4) 42.37 KJ/mol 59. If 900J/g of heat is exchanged at boiling point of 68. Ag com Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions Hard View solution > Medium
Webene 64) If 900 J gf of heat is exchanged at boling point of water then increase in entropy is 1) 43.4 J K mot 2) 87.2 J K molt 3) 900 J K mot 4) zero Solution Verified by Toppr Solve … custom threading houstonWebIf 900 J/g of heat is exchanged at boiling point of water, then what is increase in entropy? A 43.4 J/K-mole B 87.2 J/K mole C 900 J/K-mole D Zero Medium Solution Verified by Toppr Correct option is A) Was this answer helpful? 0 0 Similar questions The melting point of a solid is 200K and its latent heat of fusion is 400calmol −1. chc williamsburgWebIf \( 900 \mathrm{~J} / \mathrm{g} \) of heat is exchanged at boiling point ofP water, then what is increase in entropy?W(1) \( 43.4 \mathrm{~J} / \mathrm{K}... chcw fax numberWebCalorimetry. Calorimetry is an application of the First Law of Thermodynamics to heat transfer, and allows us to measure the enthalpies of reaction or the heat capacities of substances. From the first law we can state. Δ E Universe = Δ E System + Δ E Surrounding = 0. therefore, Δ E System = -Δ E Surrounding. custom thread pool in javaWebThe specific heat of aluminum is 900 J/ (kg·K) and that of water is 4190 J/ (kg•K). What is the final temperature of the system, assuming no heat is exchanged with the surroundings? A)35°C B)28°C C)33°C D) 31°C E)32°C Answer: E 34) E ) 32°C 9 © © © © © © © © © © chcwhs312aWeb13 okt. 2024 · In this case: Q= 900 J c= 0.902 m= ? ΔT= Tfinal - Tinitial= 38 °C - 30°C= 8°C as it is a temperature difference, it is indistinct if the temperature is expressed in ° C or ° K because the difference will be the same. So: ΔT= 8°C= 8 °K Replacing: 900 J= 0.902 *m* 8 °K 900 J= 7.216 *m 124.72 g=m The mass of aluminum is 124.72 g Advertisement custom thread ring gagesWebIf 900 J/g of heat is exchanged at boiling point of water, then what is increase in entropy? A 43.4 J/K-mole B 87.2 J/K mole C 900 J/K-mole D Zero Medium Solution Verified by … custom threadz